Subnetting VLSM Untuk 192.168.10.0/25

1. Soal

Network: 192.168.10.0/25
Kebutuhan host:

• Subnet A = 60 host
• Subnet B = 24 host
• Subnet C = 12 host
• Subnet D = 5 host

2. Urutkan dari host terbesar

Subnet	Host	Kebutuhan Block	Prefix
A	60	64	/26
B	24	32	/27
C	12	16	/28
D	5	8	/29

3. Diagram Alokasi (Tree)

192.168.10.0/25   (0 – 127)
 ├─ 192.168.10.0/26   (0 – 63)    → Subnet A (60 host)
 ├─ 192.168.10.64/27  (64 – 95)   → Subnet B (24 host)
 ├─ 192.168.10.96/28  (96 – 111)  → Subnet C (12 host)
 ├─ 192.168.10.112/29 (112 – 119) → Subnet D (5 host)
 └─ 192.168.10.120/29 (120 – 127) → Cadangan

4. Tabel Akhir Subnet

Subnet	Prefix	Network	Usable Range	Broadcast	Usable
A	/26	192.168.10.0	192.168.10.1 – 192.168.10.62	192.168.10.63	62
B	/27	192.168.10.64	192.168.10.65 – 192.168.10.94	192.168.10.95	30
C	/28	192.168.10.96	192.168.10.97 – 192.168.10.110	192.168.10.111	14
D	/29	192.168.10.112	192.168.10.113 – 192.168.10.118	192.168.10.119	6